丛昕施计逼令甘枫加入安妮医院，再找上昔日战友心胸肺外科医生章以芯（锺嘉欣饰）、外科主管麦海琪（周家怡饰）打造出一支完美团队，目的只为拼凑心中蓝图，为兴建香港第一所“儿科中心”铺路。 经历一个个病童的生死故事，令原本势成水火的丛昕与甘枫逐渐解开心结。
A men: team, individual all-round, floor exercise, pommel horse, rings, vault, parallel bars, horizontal bars, trampoline individual events;
In women, they often spend more time reviewing their lives, especially enumerating those regrets in their lives.
"Little Charlie, have you made a wish?"
巫，继承了盘古血脉，身体强横无匹。
再说，不是还有我娘么。
One platform, two terminals
宁城首富陆永年，虽已富甲一方，却仍有遗憾。因大太太沈容不能生育，陆永年遂把希望放在二太太韦一娴身上。韦一娴果不负期望，替陆家生下一名女婴，取名陆明珠。沈容虽已收养一子浩中，但毕竟不是陆家的骨血，思及未来，心生恐惧。
Because of the high DPH of two-handed weapons (damege per hit, single attack damage, the slower the initial attack speed of weapons in the game, the higher the DPH, and the normal DPH average of two-handed hammers is 4000 +), the average damage income of jewelry parts is weaker than that of other BD (the average DPH of other BD is generally less than 3000), that is to say, the second damage of the equivalent weapon of the scourge flow panel is the large number of second damage of the main hand weapon burning furnace or the prophecy blade.
于是，两人终于结婚了。婚后两人虽同一屋檐下，但住在不同的房间。年纪相差挺大的两人在生活中闹了不少笑话，然而随着日久天长，爱情也在两人之间悄悄成长。但由于之前的一次误会令到赫俊的姐姐对贞淑十分不满，加上这时赫俊以前在美国的女友回来希望挽回两人之间的爱情，贞淑和赫俊的爱情之路又能否走得完满？
三个月之后，你我一战，不死不休。
唐伯虎（张家辉）、文征明（林家栋 饰）和祝枝山（欧阳震华 饰）是苏州出名的三大才子，这天在南北才艺夺锦大赛中，他们代表江南六艺会馆出赛，结果大胜江北七星会馆。建宁王的义子子建见三人都是不可多得的人才，想招致帐下为己所用。贪财的枝山顺口答应，但伯虎和征明深知子建为人，拒绝了他的邀请。枝山答应后又后悔了，想开溜避开子建，不料反被子建捉个正着，幸好伯虎和征明及时赶到，不仅救回枝山，更赢了子建很多银子。从此子建与他们势不两立。王文宾（魏骏杰 饰）自小便有过目不忘的本领，更是学富五俥，为了扬名立万，文宾向子建自荐。子建正在寻找能人异士打败三大才子出一口怨气，于是文宾成座上客。一番恶斗又开始了！
香港警察凌风（张智霖饰）被控勾结毒贩，杀死拍档 兼好友樊毅（王阳明饰）。为求清白，凌风潜逃。督察简文珊（薛凯琪饰）是樊毅未婚妻，亲自追捕。凌风得神秘女子林音相助，寻找真相不果，绝望之际，樊毅竟死而复生，为他洗脱嫌疑。一切仿似重回正轨，其实暗著大阴谋。为正义，凌风和简文珊合力追查幕后黑手，一场黑与白的恶斗，随即展开。
Why would they do that?
Women: 500 meters, 1000 meters, 1500 meters, 3000 meters, 5000 meters;
The above is just a synchronous chain of responsibilities, We let each node function return a specific value "nextSuccessor" synchronously, To indicate whether to pass the request to the next node, we will often encounter AJAX asynchronous requests in our development. After the request is successful, we need to do something so-and-so. At this time, if we apply the above synchronous request again, it will not take effect. Let's understand and use asynchronous responsibility chain to solve this problem. We add another prototype method Chain.prototype.next to the Chain class to manually pass the request to the next node in the responsibility chain.
某对男女在某所初中成为恋人，卿卿我我，由于琐事产生误会，比起怦然心动，生气烦躁变得多了起来……后来趁着毕业就分手了。
Multi-Reactor Thread Mode
59. X.X.100
Experience Award: 9900 XP
